Tentukan penyelesaian persamaan berikut :
3^x+1 = 9^x-1
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3^x+1 = 9^x-1
[tex] \tt {3}^{x + 1} = {9}^{x - 1} [/tex]
[tex] \tt {3}^{x + 1} = {( {3}^{2} )}^{x - 1} [/tex]
[tex] \tt { \not3}^{x + 1} = { \not3}^{2x - 2} [/tex]
x + 1 = 2x - 2
x - 2x = -2 - 1
-x = -3
x = 3
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]
Jawaban:
3^x+1 = 9^x-1
3^x+1 = 3^2(x-1)
x + 1 = 2x - 2
x -2x = -2 - 1
-x = -3
x = 3
